0=-4.9t^2+27t+2.4

Solution for 0=-4.9t^2+27t+2.4 equation:

0=-4.9t^2+27t+2.4

We move all terms to the left:

0-(-4.9t^2+27t+2.4)=0

We add all the numbers together, and all the variables

-(-4.9t^2+27t+2.4)=0

We get rid of parentheses

4.9t^2-27t-2.4=0

a = 4.9; b = -27; c = -2.4;
Δ = b2-4ac
Δ = -272-4·4.9·(-2.4)
Δ = 776.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{776.04}}{2*4.9}=\frac{27-\sqrt{776.04}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{776.04}}{2*4.9}=\frac{27+\sqrt{776.04}}{9.8}
$